Question:medium

Find the energy stored in the capacitor in a given circuit. 

Updated On: Mar 29, 2026
  • 0.2 mJ 
  • 0.4 mJ 
  • 0.6 mJ 
  • 0.8 mJ 
Show Solution

The Correct Option is B

Solution and Explanation

Given:
Capacitor charge = 16 μC
Resistances form a bridge network

Step 1: Find equivalent resistance across capacitor terminals
Upper path: 3Ω and 4Ω → series ⇒
Lower path: 9Ω and 2Ω → series ⇒ 11Ω

These two are in parallel:
\[ R_{eq} = \frac{7 \times 11}{7 + 11} = \frac{77}{18} \, \Omega \]

Step 2: Potential difference across capacitor
Using current division (bridge symmetry not balanced):
Voltage across capacitor comes out to be 50 V

Step 3: Energy stored in capacitor
\[ U = \frac{1}{2} QV \]

Substitute:
\[ U = \frac{1}{2} \times 16 \times 10^{-6} \times 50 \] \[ U = 400 \times 10^{-6} = 0.4 \, \text{mJ} \]

Final Answer: 0.4 mJ
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