Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is ….. (Nearest integer).
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Use Faraday’s laws of electrolysis to relate charge, time, and current.
Faraday's law states that \( Q = I \times t \). The hydroxide ion (\( OH^- \)) concentration at \( pH = 12 \) is \( [OH^-] = 10^{-2} { M} \). For 0.6 L, the moles of \( OH^- \) are \( n = 0.6 \times 10^{-2} = 6 \times 10^{-3} { moles} \). The required charge is \( Q = n \times F = 6 \times 10^{-3} \times 96500 = 579 C \). Therefore, the current is \( I = \frac{Q}{t} = \frac{579}{300} \approx 10 A \).
