Question:medium

Differential equation of family \(y=a\cos \mu x + b\sin \mu x\) is

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Any combination of \(\sin\) and \(\cos\) leads to \(y'' + k^2 y = 0\).
Updated On: Apr 18, 2026
  • \(\frac{d^2y}{dx^2} + \mu y = 0\)
  • \(\frac{d^2y}{dx^2} - \mu^2 y = 0\)
  • \(\frac{d^2y}{dx^2} + \mu^2 y = 0\)
  • None of these
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
To form a differential equation, we differentiate the equation of the family of curves as many times as the number of arbitrary constants (here, 2: \( a \) and \( b \)) and then eliminate these constants.
Step 2: Detailed Explanation:
Given: \( y = a \cos \mu x + b \sin \mu x \).
Differentiating once with respect to \( x \): \[ \frac{dy}{dx} = -a \mu \sin \mu x + b \mu \cos \mu x \] Differentiating again with respect to \( x \): \[ \frac{d^{2}y}{dx^{2}} = -a \mu^{2} \cos \mu x - b \mu^{2} \sin \mu x \] Factor out \( -\mu^{2} \): \[ \frac{d^{2}y}{dx^{2}} = -\mu^{2} (a \cos \mu x + b \sin \mu x) \] Substituting the original expression for \( y \): \[ \frac{d^{2}y}{dx^{2}} = -\mu^{2} y \] Rearranging: \[ \frac{d^{2}y}{dx^{2}} + \mu^{2} y = 0 \].
Step 3: Final Answer:
The differential equation is \( \frac{d^{2}y}{dx^{2}} + \mu^{2} y = 0 \).
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