To determine the electric dipole moment of a system with three charges placed at the vertices of an equilateral triangle, as depicted in the situation provided, follow these steps:
Step 1: Understand the System Configuration
Consider an equilateral triangle with side length \( l \), where each vertex hosts a charge. Let the charges at the vertices be \( +q, +q, \) and \( -2q \). For simplicity, place the center of the triangle at the origin for calculation purposes.
Step 2: Define the Position Vectors
Assume the vertices of the triangle are \( A, B, \) and \( C \). The typical coordinates for the vertices of an equilateral triangle, centered at the origin, are:
Step 3: Calculate the Total Dipole Moment
The electric dipole moment \( \mathbf{p} \) is defined as the product of charge \( q \) and displacement vector \( \mathbf{d} \):
\[\mathbf{p} = q_1 \mathbf{r}_1 + q_2 \mathbf{r}_2 + q_3 \mathbf{r}_3\]
Where:
Substituting the values,
\[\begin{align*} \mathbf{p} &= q \left(0, \frac{l}{\sqrt{3}}\right) + q \left(-\frac{l}{2}, -\frac{l}{2\sqrt{3}}\right) + (-2q) \left(\frac{l}{2}, -\frac{l}{2\sqrt{3}}\right) \\ &= q \left(0, \frac{l}{\sqrt{3}}\right) - q \left(\frac{l}{2}, \frac{l}{2\sqrt{3}}\right) - q \left(l, -l/\sqrt{3}\right) \\ &= -ql \left(\frac{1}{2} + 1\right) \hat{i} + ql \left(\frac{1}{\sqrt{3}} + \frac{1}{2\sqrt{3}} - \frac{2}{2\sqrt{3}}\right) \hat{j} \\ &= -\frac{3}{2}ql \, \hat{i} + (-\sqrt{3}ql) \, \hat{j} \end{align*}\]
Step 4: Conclusion
The final electric dipole moment of the system, therefore, has only a significant \(\hat{j}\) component:
\(-\sqrt{3}ql \, \hat{j}\)
This matches the given correct answer: -\sqrt{3}ql\hat{j}