Question:medium

The electrostatic potential due to an electric dipole at a distance \( r \) varies as:

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The electric potential due to a monopole (point charge) follows a \( \frac{1}{r} \) relationship, whereas for a dipole, the potential decreases with the square of the distance, \( \frac{1}{r^2} \).
Updated On: Jan 13, 2026
  • \( r \)
  • \( \frac{1}{r^2} \)
  • \( \frac{1}{r^3} \)
  • \( \frac{1}{r} \)
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The Correct Option is B

Solution and Explanation

The electrostatic potential \( V_p \) at a distance \( r \) from the center of an electric dipole is proportional to the inverse square of the distance, \( V_p \propto \frac{1}{r^2} \). This faster decrease compared to a point charge (\( \frac{1}{r} \)) is due to the opposing charges in the dipole creating a field that diminishes more rapidly with increasing distance. Final Answer:\[\boxed{\frac{1}{r^2}}.\]
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