Question:medium

CrCl\(_3\).xNH\(_3\) can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558°C. Assuming 100\% ionization of this complex and coordination number of Cr is 6, the complex will be:

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In colligative properties like freezing point depression, the key is the number of particles in solution. Higher ionization or dissociation results in a higher change in freezing point.
Updated On: Jan 14, 2026
  • [Cr(NH\(_3\))\(_6\)]Cl\(_3\)
  • [Cr(NH\(_3\))\(_4\)]Cl\(_2\)Cl
  • [Cr(NH\(_3\))\(_5\)]Cl\(_2\)
  • [Cr(NH\(_3\))\(_3\)]Cl\(_3\)
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The Correct Option is C

Solution and Explanation

The problem concerns determining the structure of a coordination complex by analyzing its ionization and the resulting freezing point depression.

Given a 0.1 molal solution with a freezing point depression (\(\Delta T_f\)) of 0.558°C, the formula for freezing point depression, \(\Delta T_f = i \cdot K_f \cdot m\), is applied. Here, \(i\) represents the Van't Hoff factor, \(K_f\) is the cryoscopic constant (1.86 °C kg/mol for water), and \(m\) is the molality.

The Van't Hoff factor (\(i\)) is calculated as: \(i = \frac{\Delta T_f}{K_f \cdot m} = \frac{0.558}{1.86 \cdot 0.1} \approx 3\). This indicates that the complex dissociates into 3 ions.

Considering the coordination number of Cr is 6, each potential complex structure is evaluated for its dissociation:

[Cr(NH\(_3\))\(_6\)]Cl\(_3\) yields 1 complex ion and 3 Cl\(^-\) ions, totaling 4 ions, which is inconsistent with \(i = 3\).

[Cr(NH\(_3\))\(_4\)]Cl\(_2\)Cl yields 1 complex ion and 3 Cl\(^-\) ions, totaling 4 ions, which is inconsistent with \(i = 3\).

[Cr(NH\(_3\))\(_5\)]Cl\(_2\) yields 1 complex ion and 2 Cl\(^-\) ions, totaling 3 ions, which is consistent with \(i = 3\).

[Cr(NH\(_3\))\(_3\)]Cl\(_3\) yields 1 complex ion and 3 Cl\(^-\) ions, totaling 4 ions, which is inconsistent with \(i = 3\).

Therefore, the complex structure [Cr(NH\(_3\))\(_5\)]Cl\(_2\) is confirmed as correct, as it aligns with the experimentally derived Van't Hoff factor of \(i = 3\).

The identified correct structure is [Cr(NH\(_3\))\(_5\)]Cl\(_2\).

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