The problem concerns determining the structure of a coordination complex by analyzing its ionization and the resulting freezing point depression.
Given a 0.1 molal solution with a freezing point depression (\(\Delta T_f\)) of 0.558°C, the formula for freezing point depression, \(\Delta T_f = i \cdot K_f \cdot m\), is applied. Here, \(i\) represents the Van't Hoff factor, \(K_f\) is the cryoscopic constant (1.86 °C kg/mol for water), and \(m\) is the molality.
The Van't Hoff factor (\(i\)) is calculated as: \(i = \frac{\Delta T_f}{K_f \cdot m} = \frac{0.558}{1.86 \cdot 0.1} \approx 3\). This indicates that the complex dissociates into 3 ions.
Considering the coordination number of Cr is 6, each potential complex structure is evaluated for its dissociation:
[Cr(NH\(_3\))\(_6\)]Cl\(_3\) yields 1 complex ion and 3 Cl\(^-\) ions, totaling 4 ions, which is inconsistent with \(i = 3\).
[Cr(NH\(_3\))\(_4\)]Cl\(_2\)Cl yields 1 complex ion and 3 Cl\(^-\) ions, totaling 4 ions, which is inconsistent with \(i = 3\).
[Cr(NH\(_3\))\(_5\)]Cl\(_2\) yields 1 complex ion and 2 Cl\(^-\) ions, totaling 3 ions, which is consistent with \(i = 3\).
[Cr(NH\(_3\))\(_3\)]Cl\(_3\) yields 1 complex ion and 3 Cl\(^-\) ions, totaling 4 ions, which is inconsistent with \(i = 3\).
Therefore, the complex structure [Cr(NH\(_3\))\(_5\)]Cl\(_2\) is confirmed as correct, as it aligns with the experimentally derived Van't Hoff factor of \(i = 3\).
The identified correct structure is [Cr(NH\(_3\))\(_5\)]Cl\(_2\).