To determine the center of mass of the remaining portion of a circular disc after a smaller circular hole is removed, follow these steps:
Employ the formula for the center of mass of a composite body:
\(X_{\text{cm}} = \frac{A_1 X_1 + A_2 X_2}{A_1 + A_2}\)
Calculate the X-coordinate of the center of mass for the remaining area:
\(X_{\text{cm}} = \frac{400\pi \cdot 0 - 25\pi \cdot 15}{400\pi - 25\pi}\)
\(X_{\text{cm}} = \frac{-375\pi}{375\pi} = -1 \, \text{cm}\)
The center of mass is located 1 cm in the negative x-direction relative to the origin.
Therefore, the distance of the center of mass from the origin is 1.0 cm.
1.0 cm
The variation of density of a solid cylindrical rod of cross-sectional area \( a \) and length \( L \) is \( \rho=\rho_0 \frac{x^2}{L^2} \), where \( x \) is the distance from one end. The position of its centre of mass from \( x=0 \) is 