To determine the center of mass of the remaining portion of a circular disc after a smaller circular hole is removed, follow these steps:
- Start with a circular disc of radius \( R = 20 \) cm, centered at the origin \((0, 0)\).
- Cut a hole with a radius \( r = 5 \) cm such that its edge is tangent to the main disc's edge.
- The distance between the center of the hole and the center of the original disc is \( R - r = 20 \, \text{cm} - 5 \, \text{cm} = 15 \, \text{cm} \).
Employ the formula for the center of mass of a composite body:
\(X_{\text{cm}} = \frac{A_1 X_1 + A_2 X_2}{A_1 + A_2}\)
- \(A_1\) = Area of the original disc = \(\pi R^2 = \pi (20)^2 = 400\pi \, \text{cm}^2\)
- \(A_2\) = Area of the hole = \(\pi r^2 = \pi (5)^2 = 25\pi \, \text{cm}^2\)
- The center of mass of the original disc (\(X_1\)) is at \((0, 0)\).
- The center of mass of the hole (\(X_2\)) is located at \((15, 0)\), given its tangency to the edge of the main disc.
Calculate the X-coordinate of the center of mass for the remaining area:
\(X_{\text{cm}} = \frac{400\pi \cdot 0 - 25\pi \cdot 15}{400\pi - 25\pi}\)
\(X_{\text{cm}} = \frac{-375\pi}{375\pi} = -1 \, \text{cm}\)
The center of mass is located 1 cm in the negative x-direction relative to the origin.
Therefore, the distance of the center of mass from the origin is 1.0 cm.
1.0 cm