The vapour pressure of a liquid is a crucial concept in understanding how a liquid behaves under different temperature conditions. Let's analyze the changes in vapour pressure with respect to temperature to answer the question.
Concept Explanation:
Vapour pressure is the pressure exerted by a vapour in equilibrium with its liquid phase at a given temperature. As you increase the temperature of a liquid, its molecules gain kinetic energy, which overcomes intermolecular forces, allowing more molecules to escape into the vapour phase. This results in an increase in vapour pressure.
According to the Clausius-Clapeyron Equation, the relation between vapour pressure and temperature is given by:
\(\frac{d\ln P}{dT} = \frac{\Delta H_{vap}}{RT^2}\)
Where:
This shows that the natural logarithm of the vapour pressure increases with temperature, but not linearly as it involves the temperature squared.
Conclusion:
From the above explanation, we understand that the vapour pressure of a liquid increases non-linearly with increasing temperature. This is because the changes in pressure are exponential rather than linear due to the temperature dependency in the Clausius-Clapeyron equation.
Correct Answer: Increases non-linearly with increasing temperature.
The freezing point depression constant (\( K_f \)) for water is \( 1.86 \, {°C·kg/mol} \). If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, calculate the freezing point depression.