Step 1: Conceptual Understanding:
Differentiate twice to generate two extra equations and eliminate both constants.
Step 2: Explanation in Detail:
$y = Ax^2 + Bx$, $\;y' = 2Ax + B$, $\;y'' = 2A$.
From $y''$: $A = \dfrac{y''}{2}$. From $y'$: $B = y' - 2Ax = y' - xy''$.
Substituting into $y$: $y = \dfrac{y''}{2}x^2 + (y'-xy'')x = xy' - \dfrac{x^2y''}{2}$.
Multiply by $-2$: $x^2y'' - 2xy' + 2y = 0$.
Step 3: Therefore, Stating the Final Answer
$x^2\dfrac{d^2y}{dx^2} - 2x\dfrac{dy}{dx} + 2y = 0$.