Question

Based on the data given below: \[ E^\circ_{\text{Cr}_2\text{O}_7^{2-}/\text{Cr}^{3+}} = 1.33 \, \text{V}, \quad E^\circ_{\text{Cl}_2/\text{Cl}^-} = 1.36 \, \text{V}, \quad E^\circ_{\text{MnO}_4^-/\text{Mn}^{2+}} = 1.51 \, \text{V}, \quad E^\circ_{\text{Cr}^{3+}/\text{Cr}} = -0.74 \, \text{V}. \] The strongest reducing agent is:

• A. \( \text{Mn}^{2+} \)
• B. \( \text{MnO}_4^- \)
• C. \( \text{Cr} \)
• D. \( \text{Cl}^- \)

Hint:

Remember that the strongest reducing agent is the species with the most negative standard reduction potential, while the strongest oxidizing agent has the most positive potential.

Answer 1

The Correct Option is A

The species exhibiting the most negative \( E^\circ \) value functions as the strongest reducing agent. This is due to a greater propensity to lose electrons associated with more negative \( E^\circ \) values.- \( E^\circ_{\text{Mn}^{2+}/\text{MnO}_4^-} = 1.51 \, \text{V} \) (MnO4- acts as a potent oxidizing agent).- \( E^\circ_{\text{Cr}^{3+}/\text{Cr}} = -0.74 \, \text{V} \) (Cr demonstrates reducing agent properties).Consequently, \( \text{Mn}^{2+} \) possesses the most negative \( E^\circ \) and is identified as the strongest reducing agent. Final Answer: \( \text{Mn}^{2+} \).