Question

Arrange the following in the ascending order of wavelength (\( \lambda \)): 
(A) Microwaves (\( \lambda_1 \)) 
(B) Ultraviolet rays (\( \lambda_2 \)) 
(C) Infrared rays (\( \lambda_3 \)) 
(D) X-rays (\( \lambda_4 \)) 
Choose the most appropriate answer from the options given below:

• A. \( \lambda_4<\lambda_3<\lambda_1<\lambda_2 \)
• B. \( \lambda_3<\lambda_4<\lambda_1<\lambda_2 \)
• C. \( \lambda_4<\lambda_2<\lambda_3<\lambda_1 \)
• D. \( \lambda_3<\lambda_4<\lambda_2<\lambda_1 \)

Hint:

The electromagnetic spectrum orders radiation based on wavelength. Shorter wavelengths correspond to higher energy and frequency (X-rays, ultraviolet), while longer wavelengths correspond to lower energy (microwaves, infrared).

Answer 1

The Correct Option is A

The wavelengths (\( \lambda \)) of electromagnetic radiation types in the electromagnetic spectrum are ordered as follows:

• \( \lambda_4 \) (X-rays) exhibit the shortest wavelength.
• \( \lambda_3 \) (Infrared rays) possess wavelengths greater than X-rays but less than microwaves.
• \( \lambda_1 \) (Microwaves) have wavelengths exceeding infrared rays but shorter than ultraviolet rays.
• \( \lambda_2 \) (Ultraviolet rays) demonstrate the longest wavelength among all types.

Consequently, the correct sequence of wavelengths is:

\[ \lambda_4 < \lambda_3 < \lambda_1 < \lambda_2. \]

Final Answer: \( \lambda_4 < \lambda_3 < \lambda_1 < \lambda_2 \).