Question

Arrange the following in the ascending order of wavelength (\( \lambda \)): 
(A) Microwaves (\( \lambda_1 \)) 
(B) Ultraviolet rays (\( \lambda_2 \)) 
(C) Infrared rays (\( \lambda_3 \)) 
(D) X-rays (\( \lambda_4 \)) \text{Choose the most appropriate answer from the options given below:}

• A. \( \lambda_4<\lambda_3<\lambda_1<\lambda_2 \)
• B. \( \lambda_3<\lambda_4<\lambda_1<\lambda_2 \)
• C. \( \lambda_4<\lambda_2<\lambda_3<\lambda_1 \)
• D. \( \lambda_3<\lambda_4<\lambda_2<\lambda_1 \)

Hint:

The electromagnetic spectrum orders radiation based on wavelength. Shorter wavelengths correspond to higher energy and frequency (X-rays, ultraviolet), while longer wavelengths correspond to lower energy (microwaves, infrared).

Answer 1

The Correct Option is A

Wavelengths (\( \lambda \)) within the electromagnetic spectrum differ across radiation types. Specifically:
- \( \lambda_4 \) (X-rays) exhibit the shortest wavelengths. 
- \( \lambda_3 \) (Infrared rays) possess wavelengths exceeding those of X-rays but are shorter than microwaves. 
- \( \lambda_1 \) (Microwaves) have wavelengths longer than infrared rays but shorter than ultraviolet rays. 
- \( \lambda_2 \) (Ultraviolet rays) demonstrate the longest wavelengths among these types. 
Consequently, the ordered sequence is: \[ \lambda_4<\lambda_3<\lambda_1<\lambda_2. \] 
Final Answer: \( \lambda_4<\lambda_3<\lambda_1<\lambda_2 \).