Question

An organic compound undergoes first order decomposition. The time taken for decomposition to \(\dfrac{1}{8}\) and \(\dfrac{1}{10}\) of its initial concentration are \(t_{1/8}\) and \(t_{1/10}\) respectively. Find the value of \[ \frac{t_{1/8}}{t_{1/10}}\times10 \] (Given: \(\log 2 = 0.3\))

• A. \(3\)
• B. \(30\)
• C. \(9\)
• D. \(0.9\)

Hint:

For first order reactions, time ratios depend only on logarithms of concentration ratios—not on initial concentration.

Answer 1

The Correct Option is A