Question:hard
An organic compound $'A'$ is oxidized with ${Na2O2}$ followed by boiling with ${HNO3}$. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate.
Based on above observation, the element present in the given compound is :
An organic compound $'A'$ is oxidized with ${Na2O2}$ followed by boiling with ${HNO3}$. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate.
Based on above observation, the element present in the given compound is :
Updated On: Apr 12, 2026
- Sulphur
- Nitrogen
- Fluorine
- Phosphorus
Show Solution
The Correct Option is D
Solution and Explanation
Was this answer helpful?
0
Top Questions on Group 15 Elements
- The maximum covalency of a non-metallic group 15 element 'E' with the weakest E-E bond is:
- JEE Main - 2025
- Chemistry
- Group 15 Elements
- (a) Baryte,
(b) Galena,
(c) Zinc blende and
(d) Copper pyrites.
How many of these minerals are sulphide based?- JEE Main - 2022
- Chemistry
- Group 15 Elements
- The correct order of the oxidation states of nitrogen in $NO, N_2O, NO_2$ and $N_2 O_3$ is :
- JEE Main - 2019
- Chemistry
- Group 15 Elements
- Reaction of \(\mathrm{PtF_6}\) with oxygen \((\mathrm{O_2})\) gas results in the formation of an ionic compound, \(X^+Y^-\). Correct statement(s) is(are)
- JEE Advanced - 2026
- Chemistry
- Group 15 Elements
- Want to practice more? Try solving extra ecology questions todayView All Questions
