Question:medium

An isolated capacitor of capacitance 100 \(\mu\)F is charged to 32 C. If 16 C of charge is discharged from it, then its capacitance value is

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Capacitance \( C = \epsilon_0 A / d \).
Unless you change the area (\( A \)), the distance (\( d \)), or the dielectric (\( \epsilon_r \)), the capacitance will not change.
Updated On: Apr 29, 2026
  • 50 \(\mu\)F
  • 100 \(\mu\)F
  • 5 \(\mu\)F
  • 200 \(\mu\)F
  • 32 \(\mu\)F
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The Correct Option is B

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