Question

An element A of group1 shows similarity to an element B belonging to group 2. If A has maximum hydration enthalpy in group 1 then B is:

• A. Mg
• B. Be
• C. Ca
• D. Sr

Answer 1

The Correct Option is A

To solve this question, we need to understand the concept of periodic table groups and hydration enthalpy.

Group 1 Elements: This group is known as the alkali metals and includes elements such as Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Cesium (Cs), and Francium (Fr).

Group 2 Elements: This group is known as the alkaline earth metals and includes elements such as Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), and Barium (Ba).

Hydration Enthalpy: This is the amount of energy released when ions are dissolved in water. Smaller ions with a higher charge density have higher hydration enthalpies because they can attract water molecules more effectively.

Now, according to the question, element A from group 1 has the maximum hydration enthalpy. Lithium (Li) is the group 1 element with the highest hydration enthalpy due to its small size. The question asks us to find the element B belonging to group 2 that shows similarity in terms of maximum hydration enthalpy.

In group 2, Beryllium (Be) and Magnesium (Mg) have high hydration enthalpies, but among them, Magnesium (Mg) shows more similarity to Lithium (Li) because they both have relatively high hydration enthalpies and are diagonally related in the periodic table, often displaying similar chemical properties in such cases.

Therefore, the correct answer is: Mg