Order the elements Li, Be, B, C, N by increasing first ionization enthalpy. Select the correct option from the choices provided.
Ionization enthalpy generally rises across a period from left to right. However, electronic configurations cause deviations.
1. Lithium (Li): Possesses the lowest ionization enthalpy due to its facile electron loss to attain a stable noble gas configuration.
2. Boron (B): Exhibits a slightly lower ionization enthalpy than beryllium. This is because removing a p-electron from boron is less energy-intensive than removing an s-electron from beryllium's filled s-orbital.
3. Beryllium (Be): Displays a higher ionization enthalpy than lithium, attributable to its smaller size and greater effective nuclear charge. Its fully filled 2s orbital also contributes.
4. Carbon (C): Shows a higher ionization enthalpy than boron, resulting from its increased nuclear charge and reduced atomic radius.
5. Nitrogen (N): Demonstrates an exceptionally high ionization enthalpy due to its stable half-filled p-orbital configuration (2p³). Electron removal disrupts this stability.
Consequently, the elements arranged in ascending order of first ionization enthalpy are:
Li < B < Be < C < N
Final Answer:
The correct sequence is Li < B < Be < C < N