Question

A wooden block of mass 5kg rests on soft horizontal floor. When an iron cylinder of mass 25 kg is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of 0.1 ms^–2 . The action force of the system on the floor is equal to:

• A. 297 N
• B. 294 N
• C. 291 N
• D. 196 N

Answer 1

The Correct Option is C

Given:

Total mass = \( 5 \, \text{kg} + 25 \, \text{kg} = 30 \, \text{kg} \)

Acceleration due to gravity (\( g \)) = \( 9.8 \, \text{m/s}^2 \).

System weight:

\[ W = 30 \times 9.8 = 294 \, \text{N} \]

Considering downward acceleration:

Net force = \( W - N = 30 \times 0.1 \)

Rearranged equation:

\[ 294 - N = 3 \implies N = 291 \, \text{N} \]