A body with a mass of \(4 \, \text{kg}\) is subjected to two forces: \(\vec{F}_1 = 5\hat{i} + 8\hat{j} + 7\hat{k}\) and \(\vec{F}_2 = 3\hat{i} - 4\hat{j} - 3\hat{k}\). The objective is to determine the acceleration acting on the body.
The net force acting on the body is calculated as the vector sum of the applied forces:
\(\vec{F}_{\text{net}} = \vec{F}_1 + \vec{F}_2\)
Substituting the given force vectors:
\(\vec{F}_{\text{net}} = (5\hat{i} + 8\hat{j} + 7\hat{k}) + (3\hat{i} - 4\hat{j} - 3\hat{k})\)
Combining the components of the vectors:
\(\vec{F}_{\text{net}} = (5 + 3)\hat{i} + (8 - 4)\hat{j} + (7 - 3)\hat{k}\) \(\vec{F}_{\text{net}} = 8\hat{i} + 4\hat{j} + 4\hat{k}\)
Newton's second law of motion, \(\vec{F}_{\text{net}} = m \vec{a}\), is applied to find the acceleration \(\vec{a}\), where \(m\) represents the mass.
The equation for acceleration is rearranged as:
\(\vec{a} = \frac{\vec{F}_{\text{net}}}{m}\)
Inputting the calculated net force and the given mass:
\(\vec{a} = \frac{8\hat{i} + 4\hat{j} + 4\hat{k}}{4}\)
The acceleration vector is obtained by dividing each component by the mass:
\(\vec{a} = 2\hat{i} + \hat{j} + \hat{k}\)
Consequently, the acceleration of the body is \(2\hat{i} + \hat{j} + \hat{k}\).