Question

A uniform disk of mass \(50\) \(kg\) is rolling without slipping with a speed of \(0.4 \;m/s\). Find minimum energy required to bring the disk to rest (in \(J\)).

Answer 1

The correct answer is: 6 J
KE = \( \frac{1}{2}mv^2_{ω}+\frac{1}{2}(\frac{mr^2}{2})ω^2 \)
K = \( \frac{3}{4}mv^2 \)
= \( \frac{3}{4}\times50\times(4)\times(0.4) \)
= 6 J