A trisubstituted compound ‘A’, \(\text{C}_{10}\text{H}_{12}\text{O}_2\), gives neutral FeCl\(_3\) test positive. Treatment of compound ‘A’ with NaOH and CH\(_3\)Br gives \(\text{C}_{11}\text{H}_{14}\text{O}_2\), with hydroiodic acid gives methyl iodide, and with hot conc. NaOH gives a compound ‘B’, \(\text{C}_{10}\text{H}_{10}\text{O}_2\). Compound ‘A’ also decolourises alkaline KMnO\(_4\). The number of \(\pi\)-bond/s present in the compound ‘A’ is ______.
For determining the number of π bonds in a compound, carefully analyze the structure, including aromatic and aliphatic double bonds. Utilize chemical reactions (e.g., FeCl3 test, KMnO4 decolourisation to identify functional groups and confirm bond types.)
To determine the number of \(\pi\)-bonds in compound 'A', \(\text{C}_{10}\text{H}_{12}\text{O}_2\), we need to analyze its reactivity and structural components based on the given reactions:
Compound 'A' gives a positive neutral FeCl\(_3\) test, indicating the presence of a phenolic (-OH) group.
Treatment with NaOH and CH\(_3\)Br leading to \(\text{C}_{11}\text{H}_{14}\text{O}_2\) suggests a Williamson ether synthesis, implying that 'A' contains a phenolic hydrogen replaced by a methyl group.
Reaction with hydroiodic acid yielding methyl iodide confirms the presence of a methoxy group (-OCH\(_3\)) in 'A'. Combined with step 2, 'A' likely contains a structure with both -OH and -OCH\(_3\).
Treatment with hot conc. NaOH forming 'B', \(\text{C}_{10}\text{H}_{10}\text{O}_2\), suggests the removal of \(\text{H}_2\) and formation of another double bond, indicating 'A' underwent dehydrogenation.
The compound decolourises alkaline KMnO\(_4\), supporting the presence of an alkene or a reactive site that gets oxidized.
Upon analyzing the given formula, \(\text{C}_{10}\text{H}_{12}\text{O}_2\), the presence of a benzene ring (6 carbon atoms) is plausible, contributing 3 \(\pi\)-bonds. Considering steps 1 to 5, formula symmetry, and typical structural possibilities:
Therefore, compound ‘A’ contains a total of 4 \(\pi\)-bonds. The number 4 matches the provided range (4,4), confirming our solution.