A solution of aluminium chloride is electrolyzed for 30 minutes using a current of 2A. The amount of the aluminium deposited at the cathode is _________
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To find the amount of substance deposited during electrolysis, use the formula \( w = \frac{It}{96500} \times \frac{M}{n} \), where \( M \) is the molar mass and \( n \) is the valency.
The mass of Al deposited, in grams, is calculated using the formula:
\[w = \frac{I t}{96500} \times \frac{27}{3}\]
Given that \( I = 2 \, \text{A} \) and \( t = 30 \times 60 \, \text{s} \).
Substituting these values into the equation:
\[w = \frac{2 \times 30 \times 60}{96500} \times \frac{27}{3} = 0.336 \, \text{g}\]
Therefore, the deposited mass of Al is \( \boxed{0.336 \, \text{g}} \).
