Question:medium

A sinusoidal electromagnetic wave is given by \( \vec{E} = 20 \sin \left( \frac{2}{300} x - 10^6 t \right) \) propagating in a non-magnetic material. Dielectric constant of the material is.

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In non-magnetic materials, the dielectric constant can be found by comparing the wave number and angular frequency in the wave equation.
Updated On: Mar 25, 2026
  • \( 9 \times 10^4 \)
  • \( 3 \times 10^2 \)
  • 4
  • 2
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The Correct Option is C

Solution and Explanation

The problem involves finding out the dielectric constant of a non-magnetic material through which a given sinusoidal electromagnetic wave propagates. The electric field of the wave is given by:

\(\vec{E} = 20 \sin \left( \frac{2}{300} x - 10^6 t \right)\)

To solve this, we can use the formula for the wave's wave number, \(\boldsymbol{k}\), and angular frequency, \(\boldsymbol{\omega}\), which are essential for determining the speed of propagation of this wave in the medium:

  • \(k = \frac{2}{300}\)
  • \(\omega = 10^6\)

The speed of the wave, \(v\), is given by the relation:

\(v = \frac{\omega}{k}\)

Substituting the values of \(\omega\) and \(k\):

\(v = \frac{10^6}{\frac{2}{300}} = \frac{10^6 \times 300}{2} = 1.5 \times 10^8 \, \text{m/s}\)

In a vacuum, the speed of light \(c\) is \(3 \times 10^8 \, \text{m/s}\). The speed of light in a material is related to the dielectric constant \((\epsilon_r)\) by:

\(v = \frac{c}{\sqrt{\epsilon_r}} \implies \epsilon_r = \left(\frac{c}{v}\right)^2\)

Substituting the values of \(c\) and \(v\):

\(\epsilon_r = \left(\frac{3 \times 10^8}{1.5 \times 10^8}\right)^2 = (2)^2 = 4\)

Therefore, the dielectric constant of the material is 4. This matches the correct answer provided.

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