The problem involves finding out the dielectric constant of a non-magnetic material through which a given sinusoidal electromagnetic wave propagates. The electric field of the wave is given by:
\(\vec{E} = 20 \sin \left( \frac{2}{300} x - 10^6 t \right)\).
To solve this, we can use the formula for the wave's wave number, \(\boldsymbol{k}\), and angular frequency, \(\boldsymbol{\omega}\), which are essential for determining the speed of propagation of this wave in the medium:
The speed of the wave, \(v\), is given by the relation:
\(v = \frac{\omega}{k}\)
Substituting the values of \(\omega\) and \(k\):
\(v = \frac{10^6}{\frac{2}{300}} = \frac{10^6 \times 300}{2} = 1.5 \times 10^8 \, \text{m/s}\)
In a vacuum, the speed of light \(c\) is \(3 \times 10^8 \, \text{m/s}\). The speed of light in a material is related to the dielectric constant \((\epsilon_r)\) by:
\(v = \frac{c}{\sqrt{\epsilon_r}} \implies \epsilon_r = \left(\frac{c}{v}\right)^2\)
Substituting the values of \(c\) and \(v\):
\(\epsilon_r = \left(\frac{3 \times 10^8}{1.5 \times 10^8}\right)^2 = (2)^2 = 4\)
Therefore, the dielectric constant of the material is 4. This matches the correct answer provided.
The electric field of a plane electromagnetic wave, travelling in an unknown non-magnetic medium is given by,
\[ E_y = 20 \sin (3 \times 10^6 x - 4.5 \times 10^{14} t) \, \text{V/m} \] (where \(x\), \(t\) and other values have S.I. units). The dielectric constant of the medium is ____________.