Question:medium

Electromagnetic waves travel in a medium with speed \( 1.5 \times 10^8 \) m/s. The relative permeability of the medium is \( 2.0 \). The relative permittivity will be:

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The speed of light in any medium is given by \( v = \frac{c}{\sqrt{\mu_r \varepsilon_r}} \), where \( \mu_r \) and \( \varepsilon_r \) are the relative permeability and permittivity.
Updated On: Nov 26, 2025
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The Correct Option is D

Solution and Explanation

Step 1: {Apply the Speed of Light Formula}
\[v = \frac{c}{\sqrt{\mu_r \varepsilon_r}}\]Step 2: {Isolate \( \varepsilon_r \)}
\[1.5 \times 10^8 = \frac{3 \times 10^8}{\sqrt{2 \varepsilon_r}}\]\[\sqrt{2 \varepsilon_r} = 2\]\[\varepsilon_r = 2\]Therefore, the correct answer is \( 2 \).
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