Question:medium

A parallel combination of 'n' cells of emf 'E' and internal resistance each, are connected across the external resistance 'R'. If the external resistance 'R' is negligibly small, then the current 'I' through the external resistance is:

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When external resistance is negligible ($R \approx 0$), cells should always be connected in series to get maximum current. Connecting them in parallel as done here means the total current is simply equal to the current from a single cell ($I = \frac{E}{r}$), but because there are $n$ cells in parallel dividing the load, the short-circuit expression scales directly by the branch multiplier!
Updated On: May 16, 2026
  • $I=\frac{nE}{R}$
  • $I=\frac{rE}{n}$
  • $I=\frac{E}{nR}$
  • $I=\frac{E}{R}$
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The Correct Option is A

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