Question

A light ray is incident on a glass slab of thickness \(4\sqrt{3}\) cm and refractive index \(\sqrt{2}\). The angle of incidence is equal to the critical angle for the glass slab with air. The lateral displacement of the ray after passing through the glass slab is _____ cm.
(Given \(\sin 15^\circ = 0.25\))

Answer 1

Correct Answer: 2

1. Total Reactant Mass (\(m_r\)):
\[ m_r = 235.0439 \, \text{u}. \]
2. Total Product Mass (\(m_p\)): 
\[ m_p = 139.9054 + 93.9063 + 1.0086 = 234.8203 \, \text{u}. \] 
3. Disintegration Energy (\(Q\)): 
Calculate \(Q\) using the formula: 
\[ Q = (m_r - m_p)c^2. \] 
Substitute the mass values and \(c^2 \approx 931 \, \text{MeV/u}\): 
\[ Q = (235.0439 - 234.8203) \times 931. \] 
Result: 
\[ Q = 0.2236 \times 931 = 208.1716 \, \text{MeV}. \] 
Answer: \(208 \, \text{MeV}\)