The position of the image formed by a convex lens is determined using the lens formula:
\( \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \)
Where:
Given values:
Substituting these values into the lens formula:
\( \frac{1}{20} = \frac{1}{v} - \frac{1}{-30} \)
Simplifying and solving for \( v \):
\( \frac{1}{20} = \frac{1}{v} + \frac{1}{30} \)
\( \frac{1}{v} = \frac{1}{20} - \frac{1}{30} \)
Using a common denominator (60):
\( \frac{1}{v} = \frac{3}{60} - \frac{2}{60} \)
\( \frac{1}{v} = \frac{1}{60} \)
Therefore,
\( v = 60\, \text{cm} \)
The image is located \( 60\, \text{cm} \) from the lens.

A parallel beam of light travelling in air (refractive index \(1.0\)) is incident on a convex spherical glass surface of radius of curvature \(50 \, \text{cm}\). Refractive index of glass is \(1.5\). The rays converge to a point at a distance \(x \, \text{cm}\) from the centre of curvature of the spherical surface. The value of \(x\) is ___________.

