Question:medium

A fractional error in $ x $, $ y $, and $ z $ are 0.1, 0.2, and 0.5 respectively. Find the maximum fractional error in $ x^{-2} y^{3/2} z^{-2/5} $.

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To calculate the maximum fractional error in a product or quotient, add the fractional errors of each term. For powers, multiply the fractional error by the power.
Updated On: Jan 14, 2026
  • 0.2
  • 0.7
  • 0.6
  • 0.3
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understand the formula for fractional error.
For a function \( f(x, y, z) \) of multiple variables, the maximum fractional error in \( f \) is given by:\[\frac{\Delta f}{f} = \left| \frac{\partial f}{\partial x} \cdot \frac{\Delta x}{x} \right| + \left| \frac{\partial f}{\partial y} \cdot \frac{\Delta y}{y} \right| + \left| \frac{\partial f}{\partial z} \cdot \frac{\Delta z}{z} \right|\]For the function \( f(x, y, z) = x^{-2} y^{3/2} z^{-2/5} \), the fractional errors are propagated as follows.
Step 2: Calculate the partial derivatives.
Taking the logarithmic derivative yields:\[\frac{\Delta f}{f} = \left| -2 \cdot \frac{\Delta x}{x} \right| + \left| \frac{3}{2} \cdot \frac{\Delta y}{y} \right| + \left| -\frac{2}{5} \cdot \frac{\Delta z}{z} \right|\]
Step 3: Substitute the given fractional errors.
Given:\[\frac{\Delta x}{x} = 0.1, \quad \frac{\Delta y}{y} = 0.2, \quad \frac{\Delta z}{z} = 0.5\]Substituting these values:\[\frac{\Delta f}{f} = \left| -2 \cdot 0.1 \right| + \left| \frac{3}{2} \cdot 0.2 \right| + \left| -\frac{2}{5} \cdot 0.5 \right|\]\[\frac{\Delta f}{f} = 0.2 + 0.3 + 0.2 = 0.7\]
Step 4: Conclusion.
The maximum fractional error in the expression \( x^{-2} y^{3/2} z^{-2/5} \) is \( 0.7 \).
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