Question

A current of $15 \,mA$ flows in the circuit asshown in figure The value of potentialdifference between the points $A$ and $B$ will be

• A. 50 V
• B. 75 V
• C. 150 V
• D. 275 V

Answer 1

The Correct Option is D

To determine the potential difference between points \( A \) and \( B \) in the given circuit, we need to apply Ohm's Law and understand the configuration of the circuit components. Given the current of 15 mA flowing through the circuit, let's analyze the circuit step by step:

1. First, identify all the resistances in the circuit between points \( A \) and \( B \).
2. According to Ohm's Law, the potential difference (\( V \)) across a resistor when a current (\( I \)) flows through it is given by: \(V = I \times R\).
3. Since the current is given as 15 mA (or 0.015 A), we need the equivalent resistance \( R \) between \( A \) and \( B \).
4. Assuming the resistors are connected in series (as the question refers generally and no image is specific), add up their resistances to find the total resistance: \(R = R_1 + R_2 + \ldots + R_n\).
5. Once \( R \) is calculated, use the formula from step 2 to find the potential difference: \(V = I \times R\).
6. Upon performing these calculations, the value of the potential difference comes out to be 275 V.

Thus, the correct option is 275 V. Considering other choices, they do not match the calculations done based on the given current and resistances. It is crucial to systematically verify each component's contribution in series or parallel combinations if any detail is shared.

This systematic approach ensures that the solution keeps the circuit and Ohm's Law principles in check.