Question

A conducting wire connects two charged metallic spheres \(A\) and \(B\) of radii \(r_1\) and \(r_2\) respectively. The distance between the spheres is very large compared to their radii. The ratio of electric fields, \((E_A/E_B)\), at the surfaces of spheres \(A\) and \(B\) will be

• A. \(\dfrac{r_1}{r_2}\)
• B. \(\dfrac{r_2}{r_1}\)
• C. \(\dfrac{r_1^2}{r_2^2}\)
• D. \(\dfrac{r_2^2}{r_1^2}\)

Hint:

For conducting spheres connected by a wire: \[ V_A=V_B \] and since \[ E=\frac{V}{R}, \] the electric field at the surface of a sphere is inversely proportional to its radius.

Answer 1

The Correct Option is B