Question

A charge of \( 2 \, \mu\text{C} \) is placed in an electric field of intensity \( 4 \times 10^3 \, \text{N/C} \). What is the force experienced by the charge?

• A. \( 8 \times 10^{-3} \, \text{N} \)
• B. \( 8 \times 10^{-6} \, \text{N} \)
• C. \( 4 \times 10^{-3} \, \text{N} \)
• D. \( 4 \times 10^{-6} \, \text{N} \)

Hint:

The force experienced by a charge in an electric field is given by \( F = E \times q \). Ensure to use the correct units for the electric field and charge.

Answer 1

The Correct Option is A

A charge of \( q = 2 \, \mu\text{C} = 2 \times 10^{-6} \, \text{C} \) is subjected to an electric field with intensity \( E = 4 \times 10^3 \, \text{N/C} \). The objective is to determine the force acting on the charge. Step 1: Apply the force formula in an electric field The force on a charge within an electric field is calculated using the formula: \[ F = E \times q \] Here: - \( F \) represents the force, - \( E \) denotes the electric field intensity, - \( q \) signifies the charge. Step 2: Input the given values Substitute the values \( E = 4 \times 10^3 \, \text{N/C} \) and \( q = 2 \times 10^{-6} \, \text{C} \) into the formula: \[ F = (4 \times 10^3) \times (2 \times 10^{-6}) \] \[ F = 8 \times 10^{-3} \, \text{N} \] Step 3: Conclusion The calculated force experienced by the charge is \( 8 \times 10^{-3} \, \text{N} \). Answer: The force acting on the charge is \( 8 \times 10^{-3} \, \text{N} \), corresponding to option (1).