A compound 'X' absorbs 2 moles of hydrogen and 'X' upon oxidation with KMnO4 - H⁺ gives the following products:The total number of \(\sigma\) bonds present in the compound 'X' is ----.
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Count the sigma bonds in each part of the molecule to determine the total number of sigma bonds.
Compound 'X' consumes 2 moles of hydrogen, signifying a triple bond reduced to a single bond. Oxidation by KMnO4 in acidic conditions yields the following products:
CH3–C(=O)–CH3
CH3–C(=O)–OH
CH3–C(=O)–CH2–C(=O)–OH
These reactions illustrate the cleavage and oxidation of the triple bond and its substituents, resulting in ketones and carboxylic acids.
The total number of sigma bonds in the resulting products is calculated as follows:
CH3–C(=O)–CH3: 9 σ bonds
CH3–C(=O)–OH: 7 σ bonds
CH3–C(=O)–CH2–C(=O)–OH: 11 σ bonds
The sum of these sigma bonds is 9 + 7 + 11 = 27.
Therefore, the total number of sigma bonds in compound 'X' is 27.
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