\(\frac{v}{3}\)
\(\frac{v}{4}\)
\(\frac{v}{2}\)
\(\frac{v}{\sqrt 2}\)
To solve this problem, we need to understand the concept of the Doppler Effect, which explains the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. Here, a car is approaching a cliff and the sound of the horn is reflected back to the driver.
Given:
The situation involves two Doppler Effect events: first when the sound waves reach the cliff and second when the reflected waves return to the driver.
Step-by-step Solution:
The frequency heard by the cliff, \(f'\), when the car is moving towards it is given by the Doppler Effect formula:
f' = \frac{v + v_c}{v} \cdot f
Where \(v_c\) is the velocity of the car. Since the cliff is stationary, the velocity of the observer is zero.
The cliff reflects the frequency \(f'\) back towards the moving car:
f'' = \frac{v}{v - v_c} \cdot f'
Substitute the expression for \(f'\):
f'' = \frac{v}{v - v_c} \cdot \left(\frac{v + v_c}{v}\right) \cdot f
It is given that the frequency heard by the driver is \(2f\):
\frac{v}{v - v_c} \cdot \frac{v + v_c}{v} \cdot f = 2f
Cancel out \(f\) from both sides and solve:
\frac{v + v_c}{v - v_c} = 2
Cross multiply to solve for \(v_c\):
v + v_c = 2(v - v_c)
v + v_c = 2v - 2v_c
3v_c = 2v - v
3v_c = v
Therefore, v_c = \frac{v}{3}.
The velocity of the car, in terms of the velocity of sound, is \(\frac{v}{3}\). Thus, the correct answer is:
Answer: \(\frac{v}{3}\)