Question:easy

A capacitor of capacitance C has charge Q and energy stored in it is W. If the charge is increased to 3Q, the energy stored in the capacitor W' will be

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Energy in terms of charge is Q squared over 2C.
Updated On: Oct 1, 2026
  • \(9W\)
  • \(3W\)
  • \(\frac{W}{3}\)
  • \(\frac{W}{6}\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Scaling argument:
Tripling a quantity that appears squared multiplies the result by $3^2 = 9$.

Step 2: Check with $W = \frac12 QV$:
Charge triples and the voltage $V = \frac QC$ also triples, so $W = \frac12 QV$ becomes $9$ times.

Final Answer:
$W' = 9W$, option (A). \[ \boxed{9W} \]
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