Question:medium

A body initially at rest at a certain height from the ground is falling freely under gravity. At a time of one second, the body is at a height of 120 m from the ground. At a time $t=4.5\,s$, if the potential energy of the body is K times its total energy, then the value of K is (Acceleration due to gravity $=10\,ms^{-2}$)

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For freely falling bodies: \[ \frac{PE}{\text{Total Energy}} = \frac{\text{Current Height}}{\text{Initial Height}} \]
Updated On: Jun 17, 2026
  • 0.19
  • 0.81
  • 0.37
  • 0.63
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The Correct Option is A

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