Question:medium

A block of mass \(5\) kg is moving on an inclined plane which makes an angle of \(30^\circ\) with the horizontal. The coefficient of friction between the block and the inclined plane surface is \(\dfrac{\sqrt{3}}{2}\). The force to be applied on the block so that the block moves {down the plane without acceleration is ________ N. (\( g = 10 \, \text{m s}^{-2} \))}

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For constant velocity on an inclined plane, always equate forces along the plane—acceleration is zero.

Updated On: Apr 2, 2026

\(7.5\)
\(15\)
\(25\)
\(12.5\)

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The Correct Option is A

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