Question:medium

A block of mass \( 5 \, \text{kg} \) is placed on a frictionless surface. If a force of \( 10 \, \text{N} \) is applied to the block, what will be the acceleration of the block?

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Use Newton's second law: \( F = ma \) to find acceleration. The force applied is directly proportional to the acceleration for a given mass.
Updated On: Nov 26, 2025
  • \( 2 \, \text{m/s}^2 \)
  • \( 5 \, \text{m/s}^2 \)
  • \( 0.5 \, \text{m/s}^2 \)
  • \( 10 \, \text{m/s}^2 \)
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The Correct Option is A

Solution and Explanation

Step 1: Apply Newton's second law of motion \[F = ma\]Where: - \( F \) denotes the applied force - \( m \) represents the mass of the block - \( a \) signifies the accelerationProvided values: - \( F = 10 \, \text{N} \) - \( m = 5 \, \text{kg} \)To determine acceleration \( a \), the formula is rearranged as follows:\[a = \frac{F}{m} = \frac{10}{5} = 2 \, \text{m/s}^2\]Answer: The acceleration of the block is consequently \( 2 \, \text{m/s}^2 \). This corresponds to option (1).
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