Step 1: Apply Newton's second law of motion \[F = ma\]Where: - \( F \) denotes the applied force - \( m \) represents the mass of the block - \( a \) signifies the accelerationProvided values: - \( F = 10 \, \text{N} \) - \( m = 5 \, \text{kg} \)To determine acceleration \( a \), the formula is rearranged as follows:\[a = \frac{F}{m} = \frac{10}{5} = 2 \, \text{m/s}^2\]Answer: The acceleration of the block is consequently \( 2 \, \text{m/s}^2 \). This corresponds to option (1).