1. Mathematical Definition: If $A$ is a binary number, then its 2's complement $A^*$ is:
$$A^* = \text{NOT}(A) + 1$$
2. Applying the Operation Twice: Let's see what happens if we take the 2's complement of $A^*$:
$$(A^*)^* = \text{NOT}(A^*) + 1$$
Substituting $A^*$:
$$(A^*)^* = \text{NOT}(\text{NOT}(A) + 1) + 1$$
3. Logical Illustration: Let's take an example with the 4-bit number 5 ($0101_2$):
• Original Number: 0101
• 1st 2's Complement:
• Invert bits: 1010
• Add 1: $1010 + 1 = 1011$
• 2nd 2's Complement (of 1011):
• Invert bits: 0100
• Add 1: $0100 + 1 = \mathbf{0101}$
As demonstrated, performing the 2's complement operation twice returns the value to its original state. This is because the operation represents taking the negative of a number in signed arithmetic; and mathematically, $-(-A) = A$.