Question:medium

\(\frac{2×4×8×16}{(log_24)^2(log_48)^3(log_816)^4}\) equals

Updated On: Jan 15, 2026
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Solution and Explanation

Given:

\(\log_2 4 = 2,\quad \log_4 8 = \frac{3}{2},\quad \log_8 16 = \frac{4}{3}\)

Evaluate:

\[\frac{2 \times 4 \times 8 \times 16}{(\log_2 4)^2 (\log_4 8)^3 (\log_8 16)^4}\]

Substitute the given values:

\[= \frac{2 \times 4 \times 8 \times 16}{(2)^2 \times \left(\frac{3}{2}\right)^3 \times \left(\frac{4}{3}\right)^4}\]

Calculate the numerator:

\[2 \times 4 \times 8 \times 16 = (2^1)(2^2)(2^3)(2^4) = 2^{1+2+3+4} = 2^{10} = 1024\]

Compute the denominator step-by-step:

  • \((2)^2 = 4\)
  • \(\left(\frac{3}{2}\right)^3 = \frac{27}{8}\)
  • \(\left(\frac{4}{3}\right)^4 = \frac{256}{81}\)

The denominator is:

\[4 \times \frac{27}{8} \times \frac{256}{81}\]

Multiply:

\[= \frac{4 \times 27 \times 256}{8 \times 81}\]

Simplify numerator and denominator:

  • \(4 \times 27 = 108\)
  • \(108 \times 256 = 27648\)
  • \(8 \times 81 = 648\)
\[\text{Denominator} = \frac{27648}{648} = 42.666\ldots\]

Compute the final expression: 

\[\frac{1024}{42.666\ldots} = 24\]

Final Answer: \(\boxed{24}\)

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