\(\frac{2×4×8×16}{(log_24)^2(log_48)^3(log_816)^4}\) equals
Given:
\(\log_2 4 = 2,\quad \log_4 8 = \frac{3}{2},\quad \log_8 16 = \frac{4}{3}\)
Evaluate:
\[\frac{2 \times 4 \times 8 \times 16}{(\log_2 4)^2 (\log_4 8)^3 (\log_8 16)^4}\]Substitute the given values:
\[= \frac{2 \times 4 \times 8 \times 16}{(2)^2 \times \left(\frac{3}{2}\right)^3 \times \left(\frac{4}{3}\right)^4}\]Calculate the numerator:
\[2 \times 4 \times 8 \times 16 = (2^1)(2^2)(2^3)(2^4) = 2^{1+2+3+4} = 2^{10} = 1024\]Compute the denominator step-by-step:
The denominator is:
\[4 \times \frac{27}{8} \times \frac{256}{81}\]Multiply:
\[= \frac{4 \times 27 \times 256}{8 \times 81}\]Simplify numerator and denominator:
Compute the final expression:
\[\frac{1024}{42.666\ldots} = 24\]Final Answer: \(\boxed{24}\)
If \[ \log_{p^{1/2}} y \times \log_{y^{1/2}} p = 16, \] then find the value of the given expression.