\(10^{10}\) electrons enter the emitter of a junction transistor in a time of \(0.4\ \mu\text{s}\). If \(5%\) of the electrons are lost in the base, then the collector current is
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Current transfer ratio \(\alpha = \frac{I_C}{I_E}\). If base loss is \(x%\), then \(\alpha = 1 - \frac{x}{100}\). Here \(\alpha = 0.95\).