If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]
Find the emf of the cell
Ni(s) + 2 Ag+ (0.001 M) → Ni2+ (0.001 M) + 2Ag(s)
(Given that E°cell = 1.05 V, \(\frac{2.303RT}{F} = 0.059\) at 298 K)