Question:medium

$ y = e^{a \sin^{-1}(x)} \implies (1 - x^{2}) y_{n+2} - (2n+1)x y_{n+1} $ is equal to

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Leibnitz Rule helps differentiate products of functions multiple times.

Updated On: Apr 10, 2026

$-(n^2 + a^2)y_n$
$(n^2 - a^2)y_n$
$(n^2 + a^2)y_n$
$-(n^2 - a^2)y_n$

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The Correct Option is C

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\( y = e^{a \sin^{-1}(x)} \implies (1 - x^{2}) y_{n+2} - (2n+1)x y_{n+1} \) is equal to

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The Correct Option is C

Solution and Explanation

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