Question:medium
Which one of the following statements is not correct?
Which one of the following statements is not correct?
Show Hint
When dealing with redox reactions of halogens, remember the trend of oxidizing power: F₂>Cl₂>Br₂>I₂. A halogen can oxidize the halide ions below it in the group. Chlorine can oxidize Br⁻ and I⁻, but the extent of oxidation of iodine to oxoacids is usually up to the +5 state (iodic acid), not the +7 state.
Updated On: Mar 26, 2026
- Chlorine oxidises ferrous salts to ferric salts in acidic medium
- Chlorine oxidises iodine to periodic acid in water
- Chlorine acts as a bleaching agent due to oxidation
- Chlorine is manufactured by Deacon's process
Show Solution
The Correct Option is B
Solution and Explanation
Step 1: Analyze the oxidising action of Chlorine:
Chlorine water (Chlorine + Water) acts as a strong oxidising agent.
Reaction with Iodine:
\[ \text{I}_2 + 5\text{Cl}_2 + 6\text{H}_2\text{O} \to 2\text{HIO}_3 + 10\text{HCl} \]
Here, Iodine (\( \text{I}_2 \)) is oxidised to Iodic Acid (\( \text{HIO}_3 \)).
Step 2: Compare with Option (B): Option (B) states that Chlorine oxidises iodine to Periodic Acid (\( \text{HIO}_4 \)). This is incorrect. The product is Iodic Acid (\( \text{HIO}_3 \)).
Step 3: Verify other options: (A) Chlorine oxidises ferrous (\( \text{Fe}^{2+} \)) to ferric (\( \text{Fe}^{3+} \)). (Correct: \( 2\text{FeSO}_4 + \text{H}_2\text{SO}_4 + \text{Cl}_2 \to \text{Fe}_2(\text{SO}_4)_3 + 2\text{HCl} \)) (C) Bleaching action is due to oxidation by nascent oxygen from HOCl. (Correct) (D) Deacon's process is the oxidation of HCl by atmospheric oxygen in the presence of \( \text{CuCl}_2 \) to producing Chlorine. (Correct)
Step 2: Compare with Option (B): Option (B) states that Chlorine oxidises iodine to Periodic Acid (\( \text{HIO}_4 \)). This is incorrect. The product is Iodic Acid (\( \text{HIO}_3 \)).
Step 3: Verify other options: (A) Chlorine oxidises ferrous (\( \text{Fe}^{2+} \)) to ferric (\( \text{Fe}^{3+} \)). (Correct: \( 2\text{FeSO}_4 + \text{H}_2\text{SO}_4 + \text{Cl}_2 \to \text{Fe}_2(\text{SO}_4)_3 + 2\text{HCl} \)) (C) Bleaching action is due to oxidation by nascent oxygen from HOCl. (Correct) (D) Deacon's process is the oxidation of HCl by atmospheric oxygen in the presence of \( \text{CuCl}_2 \) to producing Chlorine. (Correct)
Was this answer helpful?
0
Top Questions on p -Block Elements
- Statement-I: An element ‘X’ of P-block forms a hydride H–X, which has the longest bond length, then element ‘X’ will have the shortest covalent radius.
Statement-II: An element ‘E’ of Group 15 forms hydride EH$_3$, that has least B.P. The maximum covalency of E is 4.
- JEE Main - 2026
- Chemistry
- p -Block Elements
- Two elements of p-block can form following halides XF$_3$ and YF$_3$. XF$_3$ can act as Lewis acid while YF$_3$ can act as Lewis base. Then hybridization of ‘X’ and ‘Y’ in XF$_3$ and YF$_3$ is respectively.
- JEE Main - 2026
- Chemistry
- p -Block Elements
Method used for separation of mixture of products (B and C) obtained in the following reaction is:
- JEE Main - 2026
- Chemistry
- p -Block Elements
- Given below are two statements:
Statement I: [CoBr₄]²⁻ ion will absorb light of lower energy than [CoCl₄]²⁻ ion.
Statement II: In [CoBr₄]²⁻ ion, the energy separation between the two set of d-orbitals is more than [CoCl₄]²⁻ ion.
In the light of the above statements, choose the correct answer from the options given below :- JEE Main - 2026
- Chemistry
- p -Block Elements
- Want to practice more? Try solving extra ecology questions todayView All Questions