$\textbf{Reduction potential of ions are given below:}$
\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]
The correct order of their oxidising power is:

Question

$\textbf{Choose the correct statements about the hydrides of group 15 elements.}$
A. The stability of the hydrides decreases in the order $\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3$
B. The reducing ability of the hydrides increases in the order $\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3$
C. Among the hydrides, $\text{NH}_3$ is a strong reducing agent while $\text{BiH}_3$ is a mild reducing agent.
D. The basicity of the hydrides increases in the order $\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3$
Choose the most appropriate from the option given below:

Answer 1

Solution: Standard reduction potentials (SRP) indicate the propensity of each ion to be reduced. A higher standard reduction potential signifies a greater tendency to gain electrons, meaning the ion acts as a more effective oxidizing agent.

Comparative Analysis: Based on the provided data, BrO₄⁻ exhibits the highest E^o value at 1.74 V, followed by IO₄⁻ at 1.65 V. ClO₄⁻ has the lowest value at 1.19 V. Consequently, the order of oxidizing strength determined by SRP is:

$\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-$.

$\textbf{Reduction potential of ions are given below:}$
\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]
The correct order of their oxidising power is:

The Correct Option is B

Solution and Explanation

Top Questions on p -Block Elements

Questions Asked in JEE Main exam

$\textbf{Reduction potential of ions are given below:}$\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]The correct order of their oxidising power is:

The Correct Option is B

Solution and Explanation

Top Questions on p -Block Elements

Questions Asked in JEE Main exam

$\textbf{Reduction potential of ions are given below:}$
\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]
The correct order of their oxidising power is: