Understanding the Concept:
Glucose is an aldohexose and contains an aldehyde functional group in its open-chain structure.
Step 1: Nature of glucose.
Glucose contains six carbon atoms and one aldehyde group.
Therefore, it is an aldose sugar, not a ketose sugar.
Step 2: Oxidation with bromine water.
Bromine water is a mild oxidizing agent.
It oxidizes aldehyde groups into carboxylic acids.
Thus, glucose is oxidized to gluconic acid:
\[
\mathrm{Glucose \xrightarrow{Br_2(aq)} Gluconic\ acid}
\]
Step 3: Reducing nature of glucose.
Because glucose contains an aldehyde group, it reduces:
\[
\text{Tollens' reagent}
\]
and
\[
\text{Fehling solution}
\]
Therefore, statements (2) and (4) are incorrect.
Step 4: Conclusion.
Hence, option (3) is correct.