Step 1: Recall the overall purpose of the reaction.
Hoffmann bromamide degradation converts an amide into a primary amine that has one carbon less than the starting amide.
Step 2: Check which reagents this conversion actually needs.
The starting material has to be a primary amide, $\text{R-CONH}_2$, so reagent (i) is required. Bromine, reagent (iii), is needed to brominate the nitrogen first. A base, sodium hydroxide, reagent (ii), is needed both to form the N-bromoamide and to hydrolyse the isocyanate formed later.
Step 3: Rule out the reagent that does not belong.
Chloroform, reagent (iv), is used in a completely different reaction, the carbylamine test for detecting primary amines, and plays no part in the Hoffmann degradation. \[ \text{R-CONH}_2 + \text{Br}_2 + 4\text{NaOH} \rightarrow \text{R-NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O} \]
Step 4: State the final set of reagents.
Only (i), (ii) and (iii) are used.
\[ \boxed{(i), (ii) \text{ and } (iii)} \]