Step 1: Write the overall Hoffmann bromamide reaction.
\[ RCONH_2 + Br_2 + 4NaOH \rightarrow RNH_2 + Na_2CO_3 + 2NaBr + 2H_2O \] From the balanced equation, the three reagents consumed are the amide $(i)$, $Br_2$ $(iii)$, and $NaOH$ $(ii)$.
Step 2: Confirm the role of each reagent.
The amide provides the starting material. $Br_2$ brominates the amide nitrogen. $NaOH$ (alkaline medium) facilitates the rearrangement and expels the carbonyl carbon as $CO_3^{2-}$, giving a primary amine with one carbon fewer.
Step 3: Eliminate $CHCl_3$.
Chloroform $(iv)$ is used in the Carbylamine reaction to make isocyanides from primary amines, not in Hoffmann degradation. It plays no role here and must be excluded. The correct set is $(i)$, $(ii)$, and $(iii)$.
\[ \boxed{(i),\;(ii),\;(iii)} \]