Question:medium

Which of the following is the ratio of 5\(^\text{th}\) Bohr orbit \( (r_5) \) of He\(^+\) & Li\(^{2+}\)?

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For a hydrogen-like atom, the radius of the Bohr orbit is inversely proportional to the atomic number \( Z \).
Updated On: Jan 14, 2026
  • \( \frac{2}{3} \)
  • \( \frac{3}{2} \)
  • \( \frac{9}{4} \)
  • \( \frac{4}{9} \)
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The Correct Option is A

Solution and Explanation

The Bohr radius \(r_n\) for a hydrogen-like atom is calculated using the formula: \[r_n = \frac{n^2 h^2}{4 \pi^2 m e^2 Z}\] Here, \(n\) is the principal quantum number, \(h\) is Planck's constant, \(m\) is the electron mass, \(e\) is the electron charge, and \(Z\) is the atomic number. For the 5th orbit, the atomic radius is proportional to \( \frac{n^2}{Z} \). Consequently, the ratio of the 5th Bohr orbit radius for He\(^+\) (\( Z = 2 \)) to Li\(^{2+}\) (\( Z = 3 \)) is determined as: \[\frac{r_5(\text{He}^+)}{r_5(\text{Li}^{2+})} = \frac{n^2 / Z_{\text{He}^+}}{n^2 / Z_{\text{Li}^{2+}}} = \frac{Z_{\text{Li}^{2+}}}{Z_{\text{He}^+}} = \frac{3}{2}\] The resulting ratio is \( \frac{3}{2} \).
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