



To address this problem, understanding zero-order chemical reaction characteristics is essential. In such reactions, the rate is constant and unaffected by reactant concentrations.
The rate equation for a zero-order reaction is:
\[\text{Rate} = k\]where \(k\) denotes the rate constant.
The integrated rate law for a zero-order reaction is:
\[[A] = [A]_0 - kt\]Here, \([A]\) is the reactant concentration at time \(t\), \([A]_0\) is the initial concentration, \(k\) is the rate constant, and \(t\) is the elapsed time.
This equation aligns with the linear equation form:
\[y = mx + c\]In this context, \([A]\) corresponds to \(y\), time \(t\) to \(x\), \(-k\) to the slope \(m\), and \([A]_0\) to the intercept \(c\).
Consequently, a plot of \([A]\) versus \(t\) for a zero-order reaction will yield a straight line with a negative slope. Among the given options, the correct graph representing a zero-order reaction is:
This graph clearly illustrates a linear decline in concentration over time, characteristic of a zero-order reaction.
Explanation of why other options are incorrect:
For the reaction $ A \rightarrow $ products, 
The reaction was started with 2.5 mol L\(^{-1}\) of A.
\(t_{100\%}\) is the time required for 100% completion of a reaction, while \(t_{1/2}\) is the time required for 50% completion of the reaction. Which of the following correctly represents the relation between \(t_{100\%}\) and \(t_{1/2}\) for zero order and first order reactions respectively