To determine which compound in the 3d series does not show a +3 oxidation state, let's analyze the oxidation states of each element mentioned in the options: V (Vanadium), Cr (Chromium), Mn (Manganese), and Cu (Copper).
- Vanadium (V): Vanadium can show multiple oxidation states, including +2, +3, +4, and +5. Therefore, Vanadium can exhibit a +3 oxidation state.
- Chromium (Cr): Chromium typically exhibits a variety of oxidation states such as +2, +3, and +6. Thus, Chromium can also exhibit a +3 oxidation state.
- Manganese (Mn): This element is well-known for its multiple oxidation states, including +2, +3, +4, +6, and +7. So, Manganese can exist in a +3 oxidation state.
- Copper (Cu): Copper predominantly shows +1 and +2 oxidation states. It does not typically exhibit a +3 oxidation state under normal conditions.
Given the analysis above, Copper (Cu) is the element in the 3d series which does not show a +3 oxidation state. Copper prefers +1 and +2 oxidation states because of its electronic configuration (3d104s1). It does not easily lose three electrons to achieve a +3 oxidation state due to the stable filled 3d10 configuration.
Therefore, the correct answer is: Cu.